2(x-2)-8(x-1)=2(3-x)+4(x+4)

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Solution for 2(x-2)-8(x-1)=2(3-x)+4(x+4) equation: 



2(x-2)-8(x-1)=2(3-x)+4(x+4)

We move all terms to the left:

2(x-2)-8(x-1)-(2(3-x)+4(x+4))=0

We add all the numbers together, and all the variables

2(x-2)-8(x-1)-(2(-1x+3)+4(x+4))=0

We multiply parentheses

2x-8x-(2(-1x+3)+4(x+4))-4+8=0



We calculate terms in parentheses: -(2(-1x+3)+4(x+4)), so:

2(-1x+3)+4(x+4)

We multiply parentheses

-2x+4x+6+16

We add all the numbers together, and all the variables

2x+22

Back to the equation:

-(2x+22)



We add all the numbers together, and all the variables

-6x-(2x+22)+4=0

We get rid of parentheses

-6x-2x-22+4=0

We add all the numbers together, and all the variables

-8x-18=0

We move all terms containing x to the left, all other terms to the right

-8x=18

x=18/-8

x=-2+1/4

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