y2-4(y-5)2=0

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Solution for y2-4(y-5)2=0 equation: 



y2-4(y-5)2=0

We add all the numbers together, and all the variables

y^2-4(y-5)2=0

We multiply parentheses

y^2-8y+40=0

a = 1; b = -8; c = +40;
Δ = b2-4ac
Δ = -82-4·1·40
Δ = -96
Delta is less than zero, so there is no solution for the equation

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