2(x-2)-2x=3x-(x-2)

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Solution for 2(x-2)-2x=3x-(x-2) equation: 



2(x-2)-2x=3x-(x-2)

We move all terms to the left:

2(x-2)-2x-(3x-(x-2))=0

We add all the numbers together, and all the variables

-2x+2(x-2)-(3x-(x-2))=0

We multiply parentheses

-2x+2x-(3x-(x-2))-4=0



We calculate terms in parentheses: -(3x-(x-2)), so:

3x-(x-2)

We get rid of parentheses

3x-x+2

We add all the numbers together, and all the variables

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

-(2x+2)-4=0

We get rid of parentheses

-2x-2-4=0

We add all the numbers together, and all the variables

-2x-6=0

We move all terms containing x to the left, all other terms to the right

-2x=6

x=6/-2

x=-3

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