-3x(2x-5)-4=2(-4x-6)

Solution for -3x(2x-5)-4=2(-4x-6) equation:

-3x(2x-5)-4=2(-4x-6)

We move all terms to the left:

-3x(2x-5)-4-(2(-4x-6))=0

We multiply parentheses

-6x^2+15x-(2(-4x-6))-4=0


We calculate terms in parentheses: -(2(-4x-6)), so:

2(-4x-6)

We multiply parentheses

-8x-12

Back to the equation:

-(-8x-12)


We get rid of parentheses

-6x^2+15x+8x+12-4=0

We add all the numbers together, and all the variables

-6x^2+23x+8=0

a = -6; b = 23; c = +8;
Δ = b2-4ac
Δ = 232-4·(-6)·8
Δ = 721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{721}}{2*-6}=\frac{-23-\sqrt{721}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{721}}{2*-6}=\frac{-23+\sqrt{721}}{-12}
$