2(x-2)+5(x+5)=4(x-8)+2(x-2)

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Solution for 2(x-2)+5(x+5)=4(x-8)+2(x-2) equation: 



2(x-2)+5(x+5)=4(x-8)+2(x-2)

We move all terms to the left:

2(x-2)+5(x+5)-(4(x-8)+2(x-2))=0

We multiply parentheses

2x+5x-(4(x-8)+2(x-2))-4+25=0



We calculate terms in parentheses: -(4(x-8)+2(x-2)), so:

4(x-8)+2(x-2)

We multiply parentheses

4x+2x-32-4

We add all the numbers together, and all the variables

6x-36

Back to the equation:

-(6x-36)



We add all the numbers together, and all the variables

7x-(6x-36)+21=0

We get rid of parentheses

7x-6x+36+21=0

We add all the numbers together, and all the variables

x+57=0

We move all terms containing x to the left, all other terms to the right

x=-57

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