(x+3)/2+3x=5(x-3)+(x+23)/5

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Solution for (x+3)/2+3x=5(x-3)+(x+23)/5 equation: 



(x+3)/2+3x=5(x-3)+(x+23)/5

We move all terms to the left:

(x+3)/2+3x-(5(x-3)+(x+23)/5)=0

We add all the numbers together, and all the variables

3x+(x+3)/2-(5(x-3)+(x+23)/5)=0

We calculate fractions


3x+x/()+(-(5(x-3)+(x+23)*2)/()=0



We calculate terms in parentheses: +(-(5(x-3)+(x+23)*2)/(), so:

-(5(x-3)+(x+23)*2)/(

We multiply all the terms by the denominator


-(5(x-3)+(x+23)*2)



We calculate terms in parentheses: -(5(x-3)+(x+23)*2), so:

5(x-3)+(x+23)*2

We multiply parentheses

5x+2x-15+46

We add all the numbers together, and all the variables

7x+31

Back to the equation:

-(7x+31)



We get rid of parentheses

-7x-31

Back to the equation:

+(-7x-31)



We get rid of parentheses

3x+x/()-7x-31=0

We multiply all the terms by the denominator


3x*()+x-7x*()-31*()=0

We add all the numbers together, and all the variables

x+3x*()-7x*()=0

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