2(x-10)=5(x-3)+7x

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Solution for 2(x-10)=5(x-3)+7x equation: 



2(x-10)=5(x-3)+7x

We move all terms to the left:

2(x-10)-(5(x-3)+7x)=0

We multiply parentheses

2x-(5(x-3)+7x)-20=0



We calculate terms in parentheses: -(5(x-3)+7x), so:

5(x-3)+7x

We add all the numbers together, and all the variables

7x+5(x-3)

We multiply parentheses

7x+5x-15

We add all the numbers together, and all the variables

12x-15

Back to the equation:

-(12x-15)



We get rid of parentheses

2x-12x+15-20=0

We add all the numbers together, and all the variables

-10x-5=0

We move all terms containing x to the left, all other terms to the right

-10x=5

x=5/-10

x=-1/2

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