7-5(n+2)-2n=2(5n-1)+1

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Solution for 7-5(n+2)-2n=2(5n-1)+1 equation: 



7-5(n+2)-2n=2(5n-1)+1

We move all terms to the left:

7-5(n+2)-2n-(2(5n-1)+1)=0

We add all the numbers together, and all the variables

-2n-5(n+2)-(2(5n-1)+1)+7=0

We multiply parentheses

-2n-5n-(2(5n-1)+1)-10+7=0



We calculate terms in parentheses: -(2(5n-1)+1), so:

2(5n-1)+1

We multiply parentheses

10n-2+1

We add all the numbers together, and all the variables

10n-1

Back to the equation:

-(10n-1)



We add all the numbers together, and all the variables

-7n-(10n-1)-3=0

We get rid of parentheses

-7n-10n+1-3=0

We add all the numbers together, and all the variables

-17n-2=0

We move all terms containing n to the left, all other terms to the right

-17n=2

n=2/-17

n=-2/17

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