2(x-1)+3x=5x-4(1-2x)+7

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Solution for 2(x-1)+3x=5x-4(1-2x)+7 equation: 



2(x-1)+3x=5x-4(1-2x)+7

We move all terms to the left:

2(x-1)+3x-(5x-4(1-2x)+7)=0

We add all the numbers together, and all the variables

2(x-1)+3x-(5x-4(-2x+1)+7)=0

We add all the numbers together, and all the variables

3x+2(x-1)-(5x-4(-2x+1)+7)=0

We multiply parentheses

3x+2x-(5x-4(-2x+1)+7)-2=0



We calculate terms in parentheses: -(5x-4(-2x+1)+7), so:

5x-4(-2x+1)+7

We multiply parentheses

5x+8x-4+7

We add all the numbers together, and all the variables

13x+3

Back to the equation:

-(13x+3)



We add all the numbers together, and all the variables

5x-(13x+3)-2=0

We get rid of parentheses

5x-13x-3-2=0

We add all the numbers together, and all the variables

-8x-5=0

We move all terms containing x to the left, all other terms to the right

-8x=5

x=5/-8

x=-5/8

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