2(x-1)+2((4x/2x-1))=8

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Solution for 2(x-1)+2((4x/2x-1))=8 equation: 



2(x-1)+2((4x/2x-1))=8

We move all terms to the left:

2(x-1)+2((4x/2x-1))-(8)=0



Domain of the equation: 2x-1))!=0

x∈R



We multiply parentheses

2x+2((4x/2x-1))-2-8=0

We multiply all the terms by the denominator


2x*2x-1))+2((4x-2*2x-1))-8*2x-1))=0

Wy multiply elements

4x^2-1))+2((4x-4x-1))-8*2x-1))=0

We add all the numbers together, and all the variables

4x^2-1))-8*2x-1))-1))+2((=0

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