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120=4x+8/x
We move all terms to the left:
120-(4x+8/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+4x+8/x)+120=0
We get rid of parentheses
-4x-8/x+120=0
We multiply all the terms by the denominator
-4x*x+120*x-8=0
We add all the numbers together, and all the variables
120x-4x*x-8=0
Wy multiply elements
-4x^2+120x-8=0
a = -4; b = 120; c = -8;
Δ = b2-4ac
Δ = 1202-4·(-4)·(-8)
Δ = 14272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14272}=\sqrt{64*223}=\sqrt{64}*\sqrt{223}=8\sqrt{223}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-8\sqrt{223}}{2*-4}=\frac{-120-8\sqrt{223}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+8\sqrt{223}}{2*-4}=\frac{-120+8\sqrt{223}}{-8} $
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