2(x-)/5=2(x+1)/7

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Solution for 2(x-)/5=2(x+1)/7 equation:



2(x-)/5=2(x+1)/7
We move all terms to the left:
2(x-)/5-(2(x+1)/7)=0
We add all the numbers together, and all the variables
2(+x)/5-(2(x+1)/7)=0
We calculate fractions
14x/()+(-(2(x+1)*5)/()=0
We calculate terms in parentheses: +(-(2(x+1)*5)/(), so:
-(2(x+1)*5)/(
We multiply all the terms by the denominator
-(2(x+1)*5)
We calculate terms in parentheses: -(2(x+1)*5), so:
2(x+1)*5
We multiply parentheses
10x+10
Back to the equation:
-(10x+10)
We get rid of parentheses
-10x-10
Back to the equation:
+(-10x-10)
We get rid of parentheses
14x/()-10x-10=0
We multiply all the terms by the denominator
14x-10x*()-10*()=0
We add all the numbers together, and all the variables
14x-10x*()=0

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