2(4x-5)=2/5(20x-33)

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Solution for 2(4x-5)=2/5(20x-33) equation: 



2(4x-5)=2/5(20x-33)

We move all terms to the left:

2(4x-5)-(2/5(20x-33))=0



Domain of the equation: 5(20x-33))!=0

x∈R



We multiply parentheses

8x-(2/5(20x-33))-10=0

We multiply all the terms by the denominator


8x*5(20x-33))-(2-10*5(20x-33))=0

Wy multiply elements

40x^2(2-50x(2=0

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