2(x+7)+4(9-x)=35-3(x-5)+x

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Solution for 2(x+7)+4(9-x)=35-3(x-5)+x equation: 



2(x+7)+4(9-x)=35-3(x-5)+x

We move all terms to the left:

2(x+7)+4(9-x)-(35-3(x-5)+x)=0

We add all the numbers together, and all the variables

2(x+7)+4(-1x+9)-(35-3(x-5)+x)=0

We multiply parentheses

2x-4x-(35-3(x-5)+x)+14+36=0



We calculate terms in parentheses: -(35-3(x-5)+x), so:

35-3(x-5)+x

determiningTheFunctionDomain
-3(x-5)+x+35

We add all the numbers together, and all the variables

x-3(x-5)+35

We multiply parentheses

x-3x+15+35

We add all the numbers together, and all the variables

-2x+50

Back to the equation:

-(-2x+50)



We add all the numbers together, and all the variables

-2x-(-2x+50)+50=0

We get rid of parentheses

-2x+2x-50+50=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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