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4(x-2)-8=2x+2(x-10)
We move all terms to the left:
4(x-2)-8-(2x+2(x-10))=0
We multiply parentheses
4x-(2x+2(x-10))-8-8=0
We calculate terms in parentheses: -(2x+2(x-10)), so:We add all the numbers together, and all the variables
2x+2(x-10)
We multiply parentheses
2x+2x-20
We add all the numbers together, and all the variables
4x-20
Back to the equation:
-(4x-20)
4x-(4x-20)-16=0
We get rid of parentheses
4x-4x+20-16=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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