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2(x+6)+9x^2=52
We move all terms to the left:
2(x+6)+9x^2-(52)=0
We multiply parentheses
9x^2+2x+12-52=0
We add all the numbers together, and all the variables
9x^2+2x-40=0
a = 9; b = 2; c = -40;
Δ = b2-4ac
Δ = 22-4·9·(-40)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-38}{2*9}=\frac{-40}{18} =-2+2/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+38}{2*9}=\frac{36}{18} =2 $
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