2(x+6)+7(2x-5)=4(2x-5)-3(x+6)

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Solution for 2(x+6)+7(2x-5)=4(2x-5)-3(x+6) equation: 



2(x+6)+7(2x-5)=4(2x-5)-3(x+6)

We move all terms to the left:

2(x+6)+7(2x-5)-(4(2x-5)-3(x+6))=0

We multiply parentheses

2x+14x-(4(2x-5)-3(x+6))+12-35=0



We calculate terms in parentheses: -(4(2x-5)-3(x+6)), so:

4(2x-5)-3(x+6)

We multiply parentheses

8x-3x-20-18

We add all the numbers together, and all the variables

5x-38

Back to the equation:

-(5x-38)



We add all the numbers together, and all the variables

16x-(5x-38)-23=0

We get rid of parentheses

16x-5x+38-23=0

We add all the numbers together, and all the variables

11x+15=0

We move all terms containing x to the left, all other terms to the right

11x=-15

x=-15/11

x=-1+4/11

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