2(x+5)+4(x-2)=8(x+4)-6(5-x)

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Solution for 2(x+5)+4(x-2)=8(x+4)-6(5-x) equation: 



2(x+5)+4(x-2)=8(x+4)-6(5-x)

We move all terms to the left:

2(x+5)+4(x-2)-(8(x+4)-6(5-x))=0

We add all the numbers together, and all the variables

2(x+5)+4(x-2)-(8(x+4)-6(-1x+5))=0

We multiply parentheses

2x+4x-(8(x+4)-6(-1x+5))+10-8=0



We calculate terms in parentheses: -(8(x+4)-6(-1x+5)), so:

8(x+4)-6(-1x+5)

We multiply parentheses

8x+6x+32-30

We add all the numbers together, and all the variables

14x+2

Back to the equation:

-(14x+2)



We add all the numbers together, and all the variables

6x-(14x+2)+2=0

We get rid of parentheses

6x-14x-2+2=0

We add all the numbers together, and all the variables

-8x=0

x=0/-8

x=0

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