2(7+x)-5(x+2)=7(x-2)-3(x+1)

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Solution for 2(7+x)-5(x+2)=7(x-2)-3(x+1) equation:



2(7+x)-5(x+2)=7(x-2)-3(x+1)
We move all terms to the left:
2(7+x)-5(x+2)-(7(x-2)-3(x+1))=0
We add all the numbers together, and all the variables
2(x+7)-5(x+2)-(7(x-2)-3(x+1))=0
We multiply parentheses
2x-5x-(7(x-2)-3(x+1))+14-10=0
We calculate terms in parentheses: -(7(x-2)-3(x+1)), so:
7(x-2)-3(x+1)
We multiply parentheses
7x-3x-14-3
We add all the numbers together, and all the variables
4x-17
Back to the equation:
-(4x-17)
We add all the numbers together, and all the variables
-3x-(4x-17)+4=0
We get rid of parentheses
-3x-4x+17+4=0
We add all the numbers together, and all the variables
-7x+21=0
We move all terms containing x to the left, all other terms to the right
-7x=-21
x=-21/-7
x=+3

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