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2(x+4)+3x-2=x*2x+1
We move all terms to the left:
2(x+4)+3x-2-(x*2x+1)=0
We add all the numbers together, and all the variables
3x+2(x+4)-(x*2x+1)-2=0
We multiply parentheses
3x+2x-(x*2x+1)+8-2=0
We get rid of parentheses
3x+2x-x*2x-1+8-2=0
We add all the numbers together, and all the variables
5x-x*2x+5=0
Wy multiply elements
-2x^2+5x+5=0
a = -2; b = 5; c = +5;
Δ = b2-4ac
Δ = 52-4·(-2)·5
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{65}}{2*-2}=\frac{-5-\sqrt{65}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{65}}{2*-2}=\frac{-5+\sqrt{65}}{-4} $
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