6(1+3x)=8(-2x-5)-4

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Solution for 6(1+3x)=8(-2x-5)-4 equation: 



6(1+3x)=8(-2x-5)-4

We move all terms to the left:

6(1+3x)-(8(-2x-5)-4)=0

We add all the numbers together, and all the variables

6(3x+1)-(8(-2x-5)-4)=0

We multiply parentheses

18x-(8(-2x-5)-4)+6=0



We calculate terms in parentheses: -(8(-2x-5)-4), so:

8(-2x-5)-4

We multiply parentheses

-16x-40-4

We add all the numbers together, and all the variables

-16x-44

Back to the equation:

-(-16x-44)



We get rid of parentheses

18x+16x+44+6=0

We add all the numbers together, and all the variables

34x+50=0

We move all terms containing x to the left, all other terms to the right

34x=-50

x=-50/34

x=-1+8/17

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