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2(x+4)+2=4x-2(-4+x)
We move all terms to the left:
2(x+4)+2-(4x-2(-4+x))=0
We add all the numbers together, and all the variables
2(x+4)-(4x-2(x-4))+2=0
We multiply parentheses
2x-(4x-2(x-4))+8+2=0
We calculate terms in parentheses: -(4x-2(x-4)), so:We add all the numbers together, and all the variables
4x-2(x-4)
We multiply parentheses
4x-2x+8
We add all the numbers together, and all the variables
2x+8
Back to the equation:
-(2x+8)
2x-(2x+8)+10=0
We get rid of parentheses
2x-2x-8+10=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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