2(3x+4)-(8x-4)=6

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Solution for 2(3x+4)-(8x-4)=6 equation: 



2(3x+4)-(8x-4)=6

We move all terms to the left:

2(3x+4)-(8x-4)-(6)=0

We multiply parentheses

6x-(8x-4)+8-6=0

We get rid of parentheses

6x-8x+4+8-6=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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