2(x+3)=4x-2(x-4)

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Solution for 2(x+3)=4x-2(x-4) equation: 



2(x+3)=4x-2(x-4)

We move all terms to the left:

2(x+3)-(4x-2(x-4))=0

We multiply parentheses

2x-(4x-2(x-4))+6=0



We calculate terms in parentheses: -(4x-2(x-4)), so:

4x-2(x-4)

We multiply parentheses

4x-2x+8

We add all the numbers together, and all the variables

2x+8

Back to the equation:

-(2x+8)



We get rid of parentheses

2x-2x-8+6=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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