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(3/7)x=130-x
We move all terms to the left:
(3/7)x-(130-x)=0
Domain of the equation: 7)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/7)x-(-1x+130)=0
We multiply parentheses
3x^2-(-1x+130)=0
We get rid of parentheses
3x^2+1x-130=0
We add all the numbers together, and all the variables
3x^2+x-130=0
a = 3; b = 1; c = -130;
Δ = b2-4ac
Δ = 12-4·3·(-130)
Δ = 1561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1561}}{2*3}=\frac{-1-\sqrt{1561}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1561}}{2*3}=\frac{-1+\sqrt{1561}}{6} $
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