2(x+3)/5+2=10-8x

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Solution for 2(x+3)/5+2=10-8x equation: 



2(x+3)/5+2=10-8x

We move all terms to the left:

2(x+3)/5+2-(10-8x)=0

We add all the numbers together, and all the variables

2(x+3)/5-(-8x+10)+2=0

We get rid of parentheses

2(x+3)/5+8x-10+2=0

We multiply all the terms by the denominator


2(x+3)+8x*5-10*5+2*5=0

We add all the numbers together, and all the variables

2(x+3)+8x*5-40=0

We multiply parentheses

2x+8x*5+6-40=0

Wy multiply elements

2x+40x+6-40=0

We add all the numbers together, and all the variables

42x-34=0

We move all terms containing x to the left, all other terms to the right

42x=34

x=34/42

x=17/21

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