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2(x+3)-6=4x-2(2+x)
We move all terms to the left:
2(x+3)-6-(4x-2(2+x))=0
We add all the numbers together, and all the variables
2(x+3)-(4x-2(x+2))-6=0
We multiply parentheses
2x-(4x-2(x+2))+6-6=0
We calculate terms in parentheses: -(4x-2(x+2)), so:We add all the numbers together, and all the variables
4x-2(x+2)
We multiply parentheses
4x-2x-4
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
2x-(2x-4)=0
We get rid of parentheses
2x-2x+4=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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