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(2/(x+1))+(3/5x-2))=0
Domain of the equation: (x+1))!=0
x∈R
Domain of the equation: 5x-2))!=0We get rid of parentheses
x∈R
(2/(x+1))+3/5x-2)=0
We calculate fractions
-2)+((2*5x)/10x^2+3x/10x^2=0
We add all the numbers together, and all the variables
-2)+((+2*5x)/10x^2+3x/10x^2=0
We multiply all the terms by the denominator
-2)+((+2*5x)+3x=0
We add all the numbers together, and all the variables
3x-2)+((+2*5x)=0
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