(1-y)=-3(y-2)

Solution for (1-y)=-3(y-2) equation:

(1-y)=-3(y-2)

We move all terms to the left:

(1-y)-(-3(y-2))=0

We add all the numbers together, and all the variables

(-1y+1)-(-3(y-2))=0

We get rid of parentheses

-1y-(-3(y-2))+1=0


We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)


We get rid of parentheses

-1y+3y-6+1=0

We add all the numbers together, and all the variables

2y-5=0

We move all terms containing y to the left, all other terms to the right

2y=5

y=5/2

y=2+1/2