2(x+3)+7(x-7)=3(x+6)+12

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Solution for 2(x+3)+7(x-7)=3(x+6)+12 equation: 



2(x+3)+7(x-7)=3(x+6)+12

We move all terms to the left:

2(x+3)+7(x-7)-(3(x+6)+12)=0

We multiply parentheses

2x+7x-(3(x+6)+12)+6-49=0



We calculate terms in parentheses: -(3(x+6)+12), so:

3(x+6)+12

We multiply parentheses

3x+18+12

We add all the numbers together, and all the variables

3x+30

Back to the equation:

-(3x+30)



We add all the numbers together, and all the variables

9x-(3x+30)-43=0

We get rid of parentheses

9x-3x-30-43=0

We add all the numbers together, and all the variables

6x-73=0

We move all terms containing x to the left, all other terms to the right

6x=73

x=73/6

x=12+1/6

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