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2(x+2)=8x+1-6x+3
We move all terms to the left:
2(x+2)-(8x+1-6x+3)=0
We add all the numbers together, and all the variables
2(x+2)-(2x+4)=0
We multiply parentheses
2x-(2x+4)+4=0
We get rid of parentheses
2x-2x-4+4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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