2(x+2)+2=4(x+3)

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Solution for 2(x+2)+2=4(x+3) equation:



2(x+2)+2=4(x+3)
We move all terms to the left:
2(x+2)+2-(4(x+3))=0
We multiply parentheses
2x-(4(x+3))+4+2=0
We calculate terms in parentheses: -(4(x+3)), so:
4(x+3)
We multiply parentheses
4x+12
Back to the equation:
-(4x+12)
We add all the numbers together, and all the variables
2x-(4x+12)+6=0
We get rid of parentheses
2x-4x-12+6=0
We add all the numbers together, and all the variables
-2x-6=0
We move all terms containing x to the left, all other terms to the right
-2x=6
x=6/-2
x=-3

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