G(x)=1/7x-15

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Solution for G(x)=1/7x-15 equation:



(G)=1/7G-15
We move all terms to the left:
(G)-(1/7G-15)=0
Domain of the equation: 7G-15)!=0
G∈R
We get rid of parentheses
G-1/7G+15=0
We multiply all the terms by the denominator
G*7G+15*7G-1=0
Wy multiply elements
7G^2+105G-1=0
a = 7; b = 105; c = -1;
Δ = b2-4ac
Δ = 1052-4·7·(-1)
Δ = 11053
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-\sqrt{11053}}{2*7}=\frac{-105-\sqrt{11053}}{14} $
$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+\sqrt{11053}}{2*7}=\frac{-105+\sqrt{11053}}{14} $

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