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2(x+2)+2=2(x+3)1
We move all terms to the left:
2(x+2)+2-(2(x+3)1)=0
We multiply parentheses
2x-(2(x+3)1)+4+2=0
We calculate terms in parentheses: -(2(x+3)1), so:We add all the numbers together, and all the variables
2(x+3)1
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
2x-(2x+6)+6=0
We get rid of parentheses
2x-2x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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