X2+y2=53

Solution for X2+y2=53 equation:

X2+X2=53

We move all terms to the left:

X2+X2-(53)=0

We add all the numbers together, and all the variables

2X^2-53=0

a = 2; b = 0; c = -53;
Δ = b2-4ac
Δ = 02-4·2·(-53)
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{106}}{2*2}=\frac{0-2\sqrt{106}}{4}
=-\frac{2\sqrt{106}}{4}
=-\frac{\sqrt{106}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{106}}{2*2}=\frac{0+2\sqrt{106}}{4}
=\frac{2\sqrt{106}}{4}
=\frac{\sqrt{106}}{2}
$