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2(x+2)+1=8x+9-(6x+4)
We move all terms to the left:
2(x+2)+1-(8x+9-(6x+4))=0
We multiply parentheses
2x-(8x+9-(6x+4))+4+1=0
We calculate terms in parentheses: -(8x+9-(6x+4)), so:We add all the numbers together, and all the variables
8x+9-(6x+4)
determiningTheFunctionDomain 8x-(6x+4)+9
We get rid of parentheses
8x-6x-4+9
We add all the numbers together, and all the variables
2x+5
Back to the equation:
-(2x+5)
2x-(2x+5)+5=0
We get rid of parentheses
2x-2x-5+5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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