-3(x+2)+12=4(x-3)

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Solution for -3(x+2)+12=4(x-3) equation: 



-3(x+2)+12=4(x-3)

We move all terms to the left:

-3(x+2)+12-(4(x-3))=0

We multiply parentheses

-3x-(4(x-3))-6+12=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

-3x-(4x-12)+6=0

We get rid of parentheses

-3x-4x+12+6=0

We add all the numbers together, and all the variables

-7x+18=0

We move all terms containing x to the left, all other terms to the right

-7x=-18

x=-18/-7

x=2+4/7

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