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2(x+2)+1=3(2x)
We move all terms to the left:
2(x+2)+1-(3(2x))=0
determiningTheFunctionDomain 2(x+2)-32x+1=0
We add all the numbers together, and all the variables
-32x+2(x+2)+1=0
We multiply parentheses
-32x+2x+4+1=0
We add all the numbers together, and all the variables
-30x+5=0
We move all terms containing x to the left, all other terms to the right
-30x=-5
x=-5/-30
x=1/6
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