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3(x-3)=3(2x+9)
We move all terms to the left:
3(x-3)-(3(2x+9))=0
We multiply parentheses
3x-(3(2x+9))-9=0
We calculate terms in parentheses: -(3(2x+9)), so:We get rid of parentheses
3(2x+9)
We multiply parentheses
6x+27
Back to the equation:
-(6x+27)
3x-6x-27-9=0
We add all the numbers together, and all the variables
-3x-36=0
We move all terms containing x to the left, all other terms to the right
-3x=36
x=36/-3
x=-12
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