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2(x+10)=3(x-20)
We move all terms to the left:
2(x+10)-(3(x-20))=0
We multiply parentheses
2x-(3(x-20))+20=0
We calculate terms in parentheses: -(3(x-20)), so:We get rid of parentheses
3(x-20)
We multiply parentheses
3x-60
Back to the equation:
-(3x-60)
2x-3x+60+20=0
We add all the numbers together, and all the variables
-1x+80=0
We move all terms containing x to the left, all other terms to the right
-x=-80
x=-80/-1
x=+80
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