2(x+1)x1/3=1x

Solution for 2(x+1)x1/3=1x equation:

2(x+1)x1/3=1x

We move all terms to the left:

2(x+1)x1/3-(1x)=0

We add all the numbers together, and all the variables

-1x+2(x+1)x1/3=0

We multiply all the terms by the denominator


-1x*3+2(x+1)x1=0

We multiply parentheses

2x^2-1x*3+2x=0

Wy multiply elements

2x^2-3x+2x=0

We add all the numbers together, and all the variables

2x^2-1x=0

a = 2; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·2·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*2}=\frac{2}{4}
=1/2
$