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2(x+1)=2(x-2)
We move all terms to the left:
2(x+1)-(2(x-2))=0
We multiply parentheses
2x-(2(x-2))+2=0
We calculate terms in parentheses: -(2(x-2)), so:We get rid of parentheses
2(x-2)
We multiply parentheses
2x-4
Back to the equation:
-(2x-4)
2x-2x+4+2=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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