2(x+1)-5=3(x+2)+8

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Solution for 2(x+1)-5=3(x+2)+8 equation: 



2(x+1)-5=3(x+2)+8

We move all terms to the left:

2(x+1)-5-(3(x+2)+8)=0

We multiply parentheses

2x-(3(x+2)+8)+2-5=0



We calculate terms in parentheses: -(3(x+2)+8), so:

3(x+2)+8

We multiply parentheses

3x+6+8

We add all the numbers together, and all the variables

3x+14

Back to the equation:

-(3x+14)



We add all the numbers together, and all the variables

2x-(3x+14)-3=0

We get rid of parentheses

2x-3x-14-3=0

We add all the numbers together, and all the variables

-1x-17=0

We move all terms containing x to the left, all other terms to the right

-x=17

x=17/-1

x=-17

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