15y2+27y=6

Solution for 15y2+27y=6 equation:

15y^2+27y=6

We move all terms to the left:

15y^2+27y-(6)=0

a = 15; b = 27; c = -6;
Δ = b2-4ac
Δ = 272-4·15·(-6)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-33}{2*15}=\frac{-60}{30}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+33}{2*15}=\frac{6}{30}
=1/5
$