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2(x+1)-5=-3(2-x)
We move all terms to the left:
2(x+1)-5-(-3(2-x))=0
We add all the numbers together, and all the variables
2(x+1)-(-3(-1x+2))-5=0
We multiply parentheses
2x-(-3(-1x+2))+2-5=0
We calculate terms in parentheses: -(-3(-1x+2)), so:We add all the numbers together, and all the variables
-3(-1x+2)
We multiply parentheses
3x-6
Back to the equation:
-(3x-6)
2x-(3x-6)-3=0
We get rid of parentheses
2x-3x+6-3=0
We add all the numbers together, and all the variables
-1x+3=0
We move all terms containing x to the left, all other terms to the right
-x=-3
x=-3/-1
x=+3
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