7x2+12=14x+5

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Solution for 7x2+12=14x+5 equation: 



7x^2+12=14x+5

We move all terms to the left:

7x^2+12-(14x+5)=0

We get rid of parentheses

7x^2-14x-5+12=0

We add all the numbers together, and all the variables

7x^2-14x+7=0

a = 7; b = -14; c = +7;
Δ = b2-4ac
Δ = -142-4·7·7
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{14}{14}=1$

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