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2(x+1)-1/3(2x-3)=1
We move all terms to the left:
2(x+1)-1/3(2x-3)-(1)=0
Domain of the equation: 3(2x-3)!=0We multiply parentheses
x∈R
2x-1/3(2x-3)+2-1=0
We multiply all the terms by the denominator
2x*3(2x-3)+2*3(2x-3)-1*3(2x-3)-1=0
Wy multiply elements
6x^2(2+6x(2-3x(2-1=0
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