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5/x-1/2x=6
We move all terms to the left:
5/x-1/2x-(6)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
10x/2x^2+(-x)/2x^2-6=0
We add all the numbers together, and all the variables
10x/2x^2+(-1x)/2x^2-6=0
We multiply all the terms by the denominator
10x+(-1x)-6*2x^2=0
Wy multiply elements
-12x^2+10x+(-1x)=0
We get rid of parentheses
-12x^2+10x-1x=0
We add all the numbers together, and all the variables
-12x^2+9x=0
a = -12; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-12)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-12}=\frac{-18}{-24} =3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-12}=\frac{0}{-24} =0 $
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