2(x+1)+3=3(x+2)+2

Solution for 2(x+1)+3=3(x+2)+2 equation:

2(x+1)+3=3(x+2)+2

We move all terms to the left:

2(x+1)+3-(3(x+2)+2)=0

We multiply parentheses

2x-(3(x+2)+2)+2+3=0


We calculate terms in parentheses: -(3(x+2)+2), so:

3(x+2)+2

We multiply parentheses

3x+6+2

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)


We add all the numbers together, and all the variables

2x-(3x+8)+5=0

We get rid of parentheses

2x-3x-8+5=0

We add all the numbers together, and all the variables

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3