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2(x+1)+1/2(6x+10)=27
We move all terms to the left:
2(x+1)+1/2(6x+10)-(27)=0
Domain of the equation: 2(6x+10)!=0We multiply parentheses
x∈R
2x+1/2(6x+10)+2-27=0
We multiply all the terms by the denominator
2x*2(6x+10)+2*2(6x+10)-27*2(6x+10)+1=0
Wy multiply elements
4x^2(6+4x(6-54x(6+1=0
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